f^2+9f-2=0

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Solution for f^2+9f-2=0 equation: 



f^2+9f-2=0

a = 1; b = 9; c = -2;
Δ = b2-4ac
Δ = 92-4·1·(-2)
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{89}}{2*1}=\frac{-9-\sqrt{89}}{2}
$


$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{89}}{2*1}=\frac{-9+\sqrt{89}}{2}
$

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